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2x^2+10x=-20
We move all terms to the left:
2x^2+10x-(-20)=0
We add all the numbers together, and all the variables
2x^2+10x+20=0
a = 2; b = 10; c = +20;
Δ = b2-4ac
Δ = 102-4·2·20
Δ = -60
Delta is less than zero, so there is no solution for the equation
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